Hey guys, looking for a bit of input on my BHN math for trying to determine a BHN outcome. If in theory im targeting a net BHN of 10 and I melt 2# of 12 bhn, along with 1# of 5 BHN I would add 12+12+5 = 29 , then divide by 3 which equals about 9.7 BHN. Do you agree with this math ? I have all my ingots BHN tested and separated according to BHN from my Cabin Tree tester. Im thinking this formula should get me close , then just add a bit of pure tin if needed ?
I have a lot of varied hardness, I have lead from pure (5 bhn) all the way up to 30/70 Antimony / lead nuggets.