Hello all - I'm a bit of hobby type gunsmith. A bit of background so ya'll will know a bit about my abilities as well as limitations: I've rebarreled Remington Rolling Blocks, Mauser 98 and 93 actions in the past which involved cutting threads and setting headspace. I've got a lathe and mill as well as a few other tools.
My current project is to rebarrel a Ruger MKII pistol. I understand these barrels are screwed into the tubular receiver with a "crush fit" requiring a LOT of torque to remove barrel. I just ordered this barrel to replace the damaged barrel.
Can anybody enlighten me about the two holes in the top of that barrel? Note the bullet ramp on bottom, but at the top are two holes, one in the chamber area, and the the other in the thread area which would be past the bullet. What is the purpose of those holes?
Next, on the receiver/barrel assembly I have on the bottom there is a setscrew (takes 1/16" allen wrench) that screws into receiver. Does that just tighten against the threads? OR - is there a dimple or hole the screw tightens into? Is it put in with loctite? I've put a bit of pressure and it doesn't loosen. It is a right hand thread? I "***-u-me" the barrel is also right hand threads on a Ruger MKII?
Thank you for any and all good info
Ken H>