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View Full Version : 42499 - anyone have this mold



w30wcf
07-06-2012, 09:35 AM
I'm trying to determine the diameter and depth of the hollow point.
The illustration below from the early Ideal catalogs, shows a pretty large and deep opening which, I think, is not correct(?).

The cataloged bullet weight was 195 grs. vs 210 grs of the parent bullet (42498 which is now known as the 427098).

If you do have this mold, I would appreciate knowing the upper pin & lower pin diameters and the pin depth.

http://i116.photobucket.com/albums/o25/w30wcf/Collector%20Cartridges/42498424991.jpg

Thank you,
w30wcf

beagle
07-06-2012, 11:42 AM
Don't have the mould but of the sixty some moulds I've HP'd, I've used the rule of thump of 1/2 the length of the bullet as the depth. The diameter of the HP rule of thumb is 1/3rd of the diameter of the bullet rounded off to the next largest common size.

I've derived this formula from measuring factory Lyman HP moulds over the years.

Think I'd go with a .140" diameter on that one.

Hope this helps./beagle

w30wcf
07-07-2012, 07:16 AM
beagle,
Thank you very much for the information.

I drilled a couple of 427098's with a 9/64" (.14) drill going a bit at a time and found that 3/8" depth = 195 grs.

I then tried a 5/32" drill and found that 5/16" depth = 195 grs.

I had forgotten that I had some hollow pointed 429434's that someone had given me. I checked the diameter and depth of the hollow point....
opening - 5/32" dia. tapered down to 3/32" diameter at the bottom
depth = .40".

I did some further checking on the history of the 42499 and found that by 1931, the cataloged weight had increased from 195 grs. to 200 grs. while the 42498 weight had remained constant at 210 grs.

So it appears that the hollow point dimensions had changed a bit at that time.
I found that a 1/8" drill x 5/16" deep and a 9/64" (.14) drill 1/4" deep would = the 200 gr weight.

Thanks again,
w30wcf